5h^2+3481=4h^2+3721

Solution for 5h^2+3481=4h^2+3721 equation:

5h^2+3481=4h^2+3721

We move all terms to the left:

5h^2+3481-(4h^2+3721)=0

We get rid of parentheses

5h^2-4h^2-3721+3481=0

We add all the numbers together, and all the variables

h^2-240=0

a = 1; b = 0; c = -240;
Δ = b2-4ac
Δ = 02-4·1·(-240)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*1}=\frac{0-8\sqrt{15}}{2}
=-\frac{8\sqrt{15}}{2}
=-4\sqrt{15}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*1}=\frac{0+8\sqrt{15}}{2}
=\frac{8\sqrt{15}}{2}
=4\sqrt{15}
$